Question

Greg is standing on the street corner. Simon's eyes are 6 feet off of the ground. He is looking down at a cockroach that is on the ground. If he is looking down at an angle of 40 degrees, how far is he from the cockroach?

Answer 1

Answer:

5.03 ft.

Step-by-step explanation:

Hope this helps.

Answer 2

Recall:

$\tan \theta = \dfrac{\text{Opposite}}{\text{Adjacent}}$

* See attached for the visual representation of the question.

Given:

The man is 6 feet tall

The angle of depression is 40°

Find the distance between the man the cockroach:

Let D be the distance between the man and the cockroach.

$\tan \theta = \dfrac{\text{Opposite}}{\text{Adjacent}}$

$\tan (40)= \dfrac{6}{\text{D}}$

$\text{D}= \dfrac{6}{\tan (40)}$

$\text{D} = 7.15 \text{ feet}$

Answer: He is 7.15 feet away from teh cockroach.