Grive the boolean function
f = xy'z+x'y'z+ xyz
1)List the truth table of the function.
2) Draw the logic diagram using the original
Boolean expression
3)simplify the alzebric expression uusing boolean algebra
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Answer:
3) f=xz(y+y') + x'y'z
f=xz.1+x'y'z (Inverse law)
f= xz+x'y'z
f= z(x+x'y')
f=z (x+x') (x+y') (Distributive law)
f=z.1.(x+y') (Inverse Law)
f=z(x+y') (Ans)
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