Physics, asked by pradhansushree42, 8 months ago

ground state deuteron​

Answers

Answered by anaftaj11
0

Explanation:

The ground state of the deuteron is dominated by the 3S1. thus not equal to the sum of the dipole moments of the proton and the neutron. The deuteron has a charge distribution with a radius of 2.1 fm.

Answered by tripathiakshita48
0

Answer:

The ground state of a deuteron is the lowest possible energy state of a nucleus that is made up of one proton and one neutron

Explanation:

The ground state of a deuteron is the lowest energy state of a nucleus consisting of one proton and one neutron, also known as a deuteron. The ground state is a stable state, in which the deuteron has the minimum possible energy and is at its most stable configuration.

The ground state of a deuteron has a total angular momentum of J = 1, which means that it has a magnetic dipole moment. This magnetic dipole moment can be measured using various experimental techniques, and it is an important parameter in understanding the properties of the deuteron.

In addition, the ground state energy of the deuteron is also an important parameter in nuclear physics, as it determines the stability of the deuteron and the strength of the nuclear force that binds the proton and neutron together. The ground state energy can be calculated theoretically using various models of the nuclear force, and it has been measured experimentally with high precision using techniques such as electron scattering and muonic hydrogen spectroscopy.

Overall, the ground state of a deuteron is an important and well-studied state in nuclear physics, and it plays a crucial role in understanding the properties of the deuteron and the nuclear force.

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