GRt, where is current, R
s resistance T is time, if
percentage error measuring i.R
and T are 2%, 1 and 1%
respectively, then the maximum
error measuring heat will be
a) 4%
b) 6%
c) 3%
d) 2%
Answers
Answered by
2
Answer:
a
Explanation:
ANSWER
Q=I
2
Rt
⇒
Q
ΔQ
=
I
2ΔI
+
R
ΔR
+
t
Δt
⇒
Q
ΔQ
×100=2(2)+1+1
⇒
Q
ΔQ
×100=6%
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