Question

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a) A dice is thrown twice. What is the probability that (1) Six will not come up
either side (in) Sum of the two numbers is seven (iii) Four will come up at least
once ?
OR​

Answer 1

Step-by-step explanation:

$\huge{\boxed{\underline{\mathcal{\purple{Ques}\green{tion}}}}}$

A dice is thrown twice. What is the probability that (1) Six will not come up?

$\huge{\boxed{\underline{\mathcal{\pink{Answer}}}}}$

Dice has only one 6.

So probability is 1/6.

$\huge{\boxed{\underline{\mathcal{\purple{Ques}\green{tion}}}}}$

Sum of the two numbers is seven

$\huge{\boxed{\underline{\mathcal{\pink{Answer}}}}}$

we know that 3 and 4 makes 7.

2/6 is the answer ie 1/3.

$\huge{\boxed{\underline{\mathcal{\purple{Ques}\green{tion}}}}}$

Four will come up at least

once ?

$\huge{\boxed{\underline{\mathcal{\pink{Answer}}}}}$

4 is one in a dice.

So, 1/6is the probability.

HOPE IT HELPS AND PLZ MARK IT AS BRAINLIEST

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Answer 2

This is ur correct answer❤️.