Question

-> A stone is dropped from a building a height of 30m It
accelerates at a rate of 8 m/Ssq. What will be the velocity
of the stone when to hit the ground? How long will
it take to reach the ground​

Answer 1

s=30m

a=8m/s^2

u=0

v=?

t=?

s=ut+1/2at^2

30=0×t+1/2×8×t^2

30=1/2×8×t^2

30 =4t^2

4t^2=30

t^2=30/4

t^2=15/2 sec

t=squar root15/2

v=u+at

v=0+8×square root 15/2

v=8 square root 15/2 m/s^2