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If angle A and angle B are acute angles such that cos A=cosB, then show that angle A=angle B.
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Given,
∠A and ∠B are acute angles ΔABC as shown in picture,
Now,
in ΔADC
CosA = AD/AC
in ΔBDC
CosB = AD/BC
Given,
CosA = CosB
AD/AC = AD/BC
AC = BC
We know that, in a triangle if two opposite sides are euqal, there corresponding angles will be also equal. Hence,
∠A = ∠B
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