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Answer:
ΔBDE:ΔABC
1:4
2BD=BC[D is the mid point of BC]
BE=BD=DE - 1 [ΔBDE is an equilateral triangle]
BC=AB=AC -2 [ ΔABC is an equilateral triangle]
In triangle ABC and triangle BDE
THEREFORE
BD/BC=BE/AB=DE/AC
By SSS Similarity
ΔBDE ≈ ΔABC
NOW
ar(ΔBDE)/ar(ΔABC)= [Because ratio of areas of similar
triangles is equal to the square of the
ratios of their corresponding sides]
THEREFORE
ar(ΔBDE):ar(ΔABC)=
=
=
=1/4 i.e 1:4
Step-by-step explanation:
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