Math, asked by halducente, 4 months ago

>Find the quadratic equation whose roots are -3 and 11.

>Determine an equation with roots 6 and 5/2.

>Give the equation of the function if the roots are 5 and -5 with a = 2.

>The roots of the quadratic functions are 1 and 3 when a = -4, determine the equation of the function.

>Determine the quadratic equation whose roots are -4 and -5.

please add solutions cuz they're needed:'D

Answers

Answered by ochukoogavic
1

Step-by-step explanation:

number one.

(x--3) ( x-+11)=0

(x+3) (x-11)= 0

x(x-11) +3(x-11) = 0

x²-11x +3x-33=0

x²-7x-33= 0

number two

(x-+6)(x-+5/2)= 0

(x-6)(x-5/2)= 0

take l.c.m

x(2x-5) +6(2x-5) = 0/2 cross multiply= 2x²-5x+12x-30 = 0

2x-7x-30=0

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