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find the
roots of the equation 4x + 3y 2 12
Answers
Answer:
roots of the given linear equation are (0 , 4) , (3, 0) , (1, 8/3) and (9/4).
Step-by-step explanation:
given equation is :-
4x + 3y = 12 .
we will try to put values one by one .
1) putting x = 0
→ 4x + 3y = 12
→ 4 * 0 + 3y = 12
→ 0 + 3y = 12
→ 3y = 12
dividing both sides by 3,
→ y = 4.
Therefore, roots of equation are (0 , 4).
2) putting y = 0
→ 4x + 3y = 12
→ 4x + 3 * 0 = 12
→ 4x + 0 = 12
→ 4x = 12
dividing both sides by 4,
→ x = 3.
Therefore, roots of equation are (3 , 0).
3) putting x = 1
→ 4x + 3y = 12
→ 4 * 1 + 3y = 12
→ 4 + 3y = 12
→ 3y = 12 - 4
→ 3y = 8
dividing both sides by 3,
→ y = (8/3) .
Therefore, roots of equation are (1 , 8/3).
4) putting y = 1
→ 4x + 3y = 12
→ 4x + 3 * 1 = 12
→ 4x + 3 = 12
→ 4x = 12 - 3
→ 4x = 9
dividing both sides by 4,
→ x = (9/4) .
Therefore, roots of equation are (9/4 , 1).
Hence, we can conclude that, roots of the given linear equation are (0 , 4) , (3, 0) , (1, 8/3) and (9/4).