Question

>
Find the values of
k ,it (x-2) is factor of p(x)= 2x^2 + 3x-k
​

Answer 1

Answer:

x−1 is the factor of the equation then put x=1 in these equation

(i) x

2

+x+k=0⇒(1)

2

+1+k=0⇒1+1+k=0⇒k=−2

(ii) 2x

2

+kx+

2

=0⇒2(1)

2

+k(1)+

2

=0⇒2+k+

2

=0⇒k=−2−

2

(iii) kx

2

−

2

x+1=0⇒k(1)

2

−

2

(1)+1=0⇒k−

2

+1=0⇒k=

2

−1

(iv) kx

2

−3x+k=0⇒k(1)

2

−3(1)+k=0⇒k−3+k=0⇒2k=−3⇒k=−

2

3

Answered By

Answer 2

p(x) = 2x²+3x-k

(x-2) = factor of p(x)

= x-2 = 0

= x = 2

Remainder = p(2) = 2(2)²+3(2)-k

= 2*4+6-k

= 14-k

= 14-k = 0 [ (x-2) is the factor of p(x)]

= k = 14