Question

>> A projectile is projected at an angle of 15' from horizontal. Its
horizontal range is found to be 3.5 metre. What would be its range if it
is projected at an angle of 45° from the horizontal ?

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Answer 1

ur answer is : 3km

Solution:

We know,

R=u2sin2θg

Here,

θ=15∘,

R=1.5km

=1500m

∴1500=u2gsin30∘ or , u2g=3000m

Now for same velocity and θ=45°, range of the projectile would be,

R′=u2sin90∘g

=u2g

=3000m

=3km

hope it will help u ❣️

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Answer 2

Answer:

ur answer is 3km

I hope it will help you