Question

>>cot^{2} theta - cos^2theta is equal to?<<


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Answer 1

Answer:

$cot^2x-cos^2x=cot^2xcos^2x$

Step-by-step explanation:

$=cos^2x/sin^2x-cos^2x$

$=(cos^2x-cos^2xsin^2x)/sin^2x$

$=(cos^2x(1-sin^2x))/sin^2x$

$=>(cos^2x*cos^2x)/sin^2x$

$=cos^2x*(cos^2x/sin^2x)$

$=cos^2xcot^2x$