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$\sf \: Question$



A man has Rs. 49 in coins of denominations pf Rs. 10, Rs. 5 and Re. 1. The ratio between Rs 10 coins and Rs. 5 coins is 1:2 and total coins are 15. How many coins of each denomination have the man?


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Answer 1

10x + 10x +( 15-3x)= 49

17x = 34

x=2

coins are 2 , 4 , 9

hope you got it buddy

Answer 2

Answer:

$\qquad\qquad\underline{\textsf{\textbf{ \color{magenta}{Question :-} }}}$

• A man Rs 49 in coins of denominations of Rs 10 of Rs 5 and Rs 1 . The ratio between Rs 10 coins and Rs 5 coins is 1:2 and total coins are 15 .How many coins of each denomination has the man ?

$\qquad\qquad\underline{\textsf{\textbf{ \color{red}{Solution :-} }}}$

Suppose x, y and z are the coins of Rupees 10 , 5 and 1 respectively;

According to the statements :

➙ 10x+5y+1z = 49; eq. 1

➙ x+y+z = 15; eq. 2

➙ x/y = 1/2 or x = 0.5y;

Now putting x = 0.5y in eq. 1 and eq. 2;

➽ 10*0.5y+5y+1z = 49;

➽ 10y+1z = 49; A

➽ 0.5y+y+z = 15;

➽ 1.5y+z =15; B

now solving (A-B) both the equations we get :

➽ 8.5y = 34;

➽ y = 34/8.5;

➽ y = 4

➽ x = 0.5y = 2;

➨ x+y+z = 15;

➨ 2+4+z = 15;

➨ z = 15-6 = 9