>>only solve by use of relative motion<< Two objects moving along the same straight line are leaving point A with an acceleration a, 2a & velocity 2 u, u respectively at time t = 0. The distance moved by the object with respect to point A when one object overtakes the other is au2/a. Here a is an integer. Find a :
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Answer:
Let both will meet at point B
x=2ut+1/2at
2
x=ut+
2
1
(2a)t
2
So 2ut+
2
1
at
2
=ut+at
2
ut=
2
1
at
2
⇒t=
a
2u
So x=2u(
a
2u
)+
2
1
a(
a
2u
)
2
=
a
6u
2
solution
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