Question

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Answer 1

$\huge\sf\fbox\red{Question-:}$

balance the following reaction in basic medium -:

MnO⁴(aq) + Br(aq) ⟹ MnO²(5) + BrO³(aq)

$\huge\sf\fbox\pink{Answer-:}$

MnO4- ⟹ MnO2

MnO4- ⟹ MnO2 + 2H2O ... to balance oxygens

MnO4- + 4H+ ⟹ MnO2 + 2H2O ... to balance hydrogens

MnO4- + 4H+ + 4OH- ⟹ MnO2 + 2H2O + 4OH- ... because it is in basic solution

MnO4- + 4H2O + 3e- ⟹ MnO2 + 2H2O + 4OH- ... to balance charge

$\blue{MnO4- + 2H2O + 3e- ⟹ MnO2 + 4OH-}$REDUCTION HALF REACTION

Br- ⟹ BrO3-

Br- + 3H2O ⟹ BrO3- ... to balance oxygens

Br- + 3H2O ⟹ BrO3- + 6H+ ... to balance hydrogens

Br- + 3H2O + 6OH- ⟹ BrO3- + 6H+ + 6OH- ... because it is in basic solution

Br- + 3H2O + 6OH- ⟹ BrO3- + 6H2O + 6e- ... to balance charge

$\blue{Br- + 6OH- ⟹ BrO3- + 3H2O + 6e-}$OXIDATION HALF REACTION

Multiply reduction half reaction by 2 to equalize electrons, and add to oxidation half reaction and cancel common items to get the final balanced equation:

2MnO4- + 4H2O + 6e- ⟹ 2MnO2 + 8OH-

Br- + 6OH- ⟹ BrO3- + 3H2O + 6e-

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$\sf\fbox\green{2MnO4- + H2O + Br- ⟹ 2MnO2 + 2OH- + BrO3-}$ $\bold{balanced\:for\:mass\:and\:charge}$

Answer 2

$\huge\bold\red{ \: Question}$

Balance the following reaction in basic medium -:

MnO⁴(aq) + Br(aq) ⟹ MnO²(5) + BrO³(aq)

$\huge\bold\red{➡ \:Answer }$

MnO4- ⟹ MnO2

MnO4- ⟹ MnO2 + 2H2O ... to balance oxygens

MnO4- + 4H+ ⟹ MnO2 + 2H2O ... to balance hydrogens

MnO4- + 4H+ + 4OH- ⟹ MnO2 + 2H2O + 4OH- ... because it is in basic solution

MnO4- + 4H2O + 3e- ⟹ MnO2 + 2H2O + 4OH- ... to balance charge

$\blue{MnO4- + 2H2O + 3e- ⟹ MnO2 + 4OH-}MnO4−+2H2O+3e−⟹MnO2+4OH− REDUCTION HALF REACTION$

Br- ⟹ BrO3-

Br- + 3H2O ⟹ BrO3- ... to balance oxygens

Br- + 3H2O ⟹ BrO3- + 6H+ ... to balance hydrogens

Br- + 3H2O + 6OH- ⟹ BrO3- + 6H+ + 6OH- ... because it is in basic solution

Br- + 3H2O + 6OH- ⟹ BrO3- + 6H2O + 6e- ... to balance charge

$\blue{Br- + 6OH- ⟹ BrO3- + 3H2O + 6e-}Br−+6OH−⟹BrO3−+3H2O+6e− OXIDATION HALF REACTION$

Multiply reduction half reaction by 2 to equalize electrons, and add to oxidation half reaction and cancel common items to get the final balanced equation:

2MnO4- + 4H2O + 6e- ⟹ 2MnO2 + 8OH-

Br- + 6OH- ⟹ BrO3- + 3H2O + 6e-

$2MnO4- + H2O + Br- ⟹ 2MnO2 + 2OH- + BrO3- \bold{balanced\:for\:mass\:and\:charge}balancedformassandcharge$