Question

>>Two devices of rating 22 W; 220 V and 11 W; 220 V are connected in series. The combination is connected across 440 V mains. The fuse of which of the two devices is likely to burn when the switch is on? Justify your name!


FASTEST ANSWER WILL BE MARKED AS BRAINLIEST!

Answer 1

Answer:

$\tt \red{ANSWER}$

✍️The fuse of device of rating 11W; 220V will burn.

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$R = \frac{ { V}^{2} }{W}$

$Resistance \: \: of \: \: 11 W \: \: device = \frac{( {220}^{2}) }{11} = 4400$

$Resistance \: \: of \: \: 22 W \: \: device = \frac{( {220}^{2}) }{22} = 2200$

∴ Resistance of 11W device will be two times then that of the device of 44w.

$I = \frac{V}{R} = \frac{440}{5500} = 0.08$

∴ Voltage across 11W = I × R = 0.8× 4400= 352 V

∴ Voltage across 22W = I × R = 0.8× 2200 = 176 V

352V across the device of 11W ; 220V rating is sufficient to burn.

✍️ THEREFORE, The fuse of device of rating 11W; 220V will burn.

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Answer 2

Answer:

The switch of both devices will burn as they have a voltage of 220 V and the voltage connected to the mains is 440 V ;

And also, they both are connected in series,

So, Both will burn.

Hope it helps u !!!!!!!

Please mark my answer as the BRAINLIEST.

By - Rishi Bhardwaj