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Prove that cotA+cosecA-1÷
cotA - cosecA+ 1
I + cosA÷
Sin A
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Answer:
cosecA+cotA−1
we know that,cosec²A−cot²A=1
substituting this in the numerator,
(cotA−cosecA+1)
cosecA+cotA−(cosec²A−cot²A)
x²−y²=(x+y)(x−y)
(cotA−cosecA+1)
cosecA+cotA−(cosecA+cotA)(cosecA−cotA)
taking common
(cotA−cosecA+1)
(cosecA+cotA)(1−cosecA+cotA)
cancelling like terms in numerator and denominator
we are left with cosecA+cotA=
sinA
1
+
sinA
cosA
=
sinA
(1+cosA)
Step-by-step explanation:
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