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The area a trapezium & 40cm^2. Its
Parallel sides & are 12cm and 8cm. The
distance between the Paralll sides is
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Answer:
Distance between parallel sides 12 cm and 8 cm is 4 cm.
Step-by-step explanation:
To find:-
Distance between parallel sides.
Solution:-
Given that,
Area of trapezium is 40 cm².
Length of parallel sides are 12 cm and 8 cm.
Area of trapezium = (a + b)/2 × h
Here, a and b are parallel sides .
And h is distance between parallel sides.
So,
➝ 40 = (12 + 8)/2 × h
➝ 40 = 20/2 × h
➝ 40 × 2 = 20 × h
➝ 80 = 20 × h
➝ 80/20 = h
➝ 4 = h
Or, ➝ h = 4
Verification:-
➝ 40 = (12 + 8)/2 × h
Put h = 4
➝ 40 = (12 + 8)/2 × 4
➝ 40 = 20/2 × 4
➝ 40 = 10 × 4
➝ 40 = 40
Hence, Verified!!.
h is distance between parallel sides which is 4 cm.
Therefore,
Distance between parallel sides 12 cm and 8 cm is 4 cm.
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