Math, asked by madhuramadhurab19, 4 months ago

>
The area a trapezium & 40cm^2. Its
Parallel sides & are 12cm and 8cm. The
distance between the Paralll sides is​

Answers

Answered by yusraayyubkhan2007
1

Answer:

Distance between parallel sides 12 cm and 8 cm is 4 cm.

Step-by-step explanation:

To find:-

Distance between parallel sides.

Solution:-

Given that,

Area of trapezium is 40 cm².

Length of parallel sides are 12 cm and 8 cm.

Area of trapezium = (a + b)/2 × h

Here, a and b are parallel sides .

And h is distance between parallel sides.

So,

➝ 40 = (12 + 8)/2 × h

➝ 40 = 20/2 × h

➝ 40 × 2 = 20 × h

➝ 80 = 20 × h

➝ 80/20 = h

➝ 4 = h

Or, ➝ h = 4

Verification:-

➝ 40 = (12 + 8)/2 × h

Put h = 4

➝ 40 = (12 + 8)/2 × 4

➝ 40 = 20/2 × 4

➝ 40 = 10 × 4

➝ 40 = 40

Hence, Verified!!.

h is distance between parallel sides which is 4 cm.

Therefore,

Distance between parallel sides 12 cm and 8 cm is 4 cm.

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