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A right triangle ABC with sides 6m, 8m and 10m is revolved about the side 8m, then the volume of the solid so obtained is a 25π b 50π c 96π d 150π
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The cone so formed has h= 8cm as the height and base radius as r= 6cm and slant height as l=10cm
volume =1/3\piπ r^{2}r
2
h
=1/3*3.14*6*6*8
=301.44cubic cm
curved surface area=\piπ rl
=3.14*6*10
=188.4 square cm
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