Question

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hru all??

A stone is dropped from the roof of a building . It takes 4 seconds to reach the ground . Find the height of the building . (Take g = 9.8 m/s^2)
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Answer 1

Answer:

24.5

Step-by-step explanation:

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Answer 2

Given:

Time to reach the ground, $t = 4s$

Initial Velocity, $u = 0$ [stationary before dropped]

Acceleration, $a = g = 9.8 \, ms^{-1}$

To find:

Height of the building, $s$

Using the second equation of motion,

$s = ut \, + (1/2)at^{2}\\\\\implies s = 0\, + (1/2)(9.8)(4)^{2}\\\implies s = (9.8)(8)\\\implies \bf \underline {s = 78.4 \, m}$

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