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If sec theta+tan theta=X then sec theta=
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I have written p in place of theta
sec p = x – tan p
squaring both the sides
sec2 p = x2 – 2* x* tan p + tan2 p
sec2 p – tan2 p = x2 – 2* x* tan p
x2 – 2* x* tan p – 1 = 0
2* x* tan p = x2 – 1
tan p = (x2 – 1) / 2 x
sec p = x – tan p
squaring both the sides
sec2 p = x2 – 2* x* tan p + tan2 p
sec2 p – tan2 p = x2 – 2* x* tan p
x2 – 2* x* tan p – 1 = 0
2* x* tan p = x2 – 1
tan p = (x2 – 1) / 2 x
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