Question

^^GUD NIGHT^^



If 12th and 22nd term of an ap are 42 and 62 respectively find the 25th term​

Answer 1

General term of an AP,

$a_{n} = a + (n-1)d$

where a is the first term and d is the common difference

Given:

$a_{12} = a+11d = 42$.........(1)

$a_{22} = a+21d = 62$.........(2)

Solving (1) and (2)

$a = 20$

$d = 2$

Hence the $25^{th}$ term,

$a_{25} = a +24d$

$a_{25} = 20+48$

$a_{25} = 68$

Hence the $25^{th}$ term is $68$

HOPE IT HELPS !!

Answer 2

Answer:

Step-by-step explanation:

a+11d=42

a+21d=62

[_] [_]   [_]

----------------

   -10d=-20

       d=-20/-10

    ---------------

a+11d=42

a+11*2=42

a+22=42

a=42-22

a=20

-------------

25th term= a+24d

=20+24*2

=20+48

=68

---------

HOPE IT HELPS YOU

PLEASE MARK ME AS BRAINLIEST