Guess the last number in the given series
12, 33, 74, 45, 36,
(Note: Answer must contain only digits without any additional space)
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HELLO DEAR,
Given : The number are 12, 33, 74, 45, 36.
we have to find last number.
Solution: If we look the digit at ones place from left to right then we get the number at ones place is going like 2,3,4,5,6.
So, next digit would be 7 ,because above digits are increasing in (n + 1) formate.
Also,
Taking tens digit of given numbers.
1 3 7 4 3
(1^2 - 0) = 1
(2^2 - 1) = 4
(3^2 - 2) = 7
(4^2 - 3) = 13 = 1 + 3 = 4
(5^2 - 4) = 21 = 1 + 2 = 3
(6^2 - 5) = 31 = 3 + 1 = 4
{n^2-(n-1)} digits added until converted in single digit.
Digit at unit place
2 3 4 5 6
Hence ,next number in theseries should be 47.
OR
GIVEN BY AMITGARG SIR
12
12 + 21 = 33
33 + 41 = 74
74 + 61 = 135 = 45 ( 1 + 3 = 4)
45 + 81 = 126 = 36 ( 1 + 2 = 3)
36 + 101 = 137 = 47 (1 + 3 = 4)
Hence,
next term in sequence would be 47.
Tₙ₊₁ = Tₙ + 20n + 1 ( where Digits other than unit digits added to form a single digits for tens place).
I HOPE IT'S HELP YOU DEAR,
THANKS
Given : 12, 33, 74, 45, 36,
To find : last number in the given series
Solution:
12, 33, 74, 45, 36,
Taking Tens digit 1st
1 3 7 4 3
1² = 1
2² - 1 = 3
3² - 2 = 7
4² - 3 = 13 = 1 + 3 = 4
5² - 4 = 21 = 2 + 1 = 3
6² - 5 = 31 = 3 + 1 = 4
n² - (n - 1) digits added until converted in single digit
Digits at unit place
2 3 4 5 6
so next digit would be 7
n + 1
Hence next number in series should be 47.
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