GUESSING THE DAY
ZEllER'S RULE: FIND THE DAY FOR GIVEN DATE QUICKLY
With this technique named after its founder Zeller, you can solve any 'Dates and Calendars' problems. ZEllER’S rule can
be used to find the day on any particular date in the calendar in the history. All you have to know is the formula given
below and how to use it.
ZEllER’S Rule Formula
F = K + [(13×M – 1)/5] + D + [D/4] + [C/4] -2C
Where,
1) K = Date. So, for 27/06/2019, we take K = 27 In
Zeller's rule, months start from March.
2) M= Month Number
Remember that month start from March in this formula. So March = 1
April = 2
May = 3
June = 4
July = 5
August= 6
September= 7
October= 8
November= 9
December= 10
January= 11
February= 12
So, for 27/06/2019, M = 4
3) D = last two digits of the year
So, in our example of 27/06/2019, the value of D is 19
4) C = The first two digits of century
So, in our example of 27/06/2019, the value of C is 20.
Let us now calculate the day for 27/06/2019 with the above formula
F = K + [(13×M – 1)/5] + D + [D/4] + [C/4] -2C
F = 27 + [(13×4 – 1)/5] + 19 + [19/4] + [20/4] -2× 20
Therefore,
F = 27 + 10.2 + 19 + 4.75 + 5 – 40
[We have to consider only the integral value and ignore the value after decimal. So, the
equation changes a bit as shown below. We have just removed value after decimal]
F = 27 + 10 + 19 + 4 + 5 – 40
i.e. F = 25
Now that you have a numerical value for the day, divide the number by 7. We need the remainder
only. For example in this case, the remainder is 4.
Now, match the remainder with the chart below:
0 = Sunday
1 = Monday
2 = Tuesday
3 = Wednesday
4 = Thursday
5 = Friday
6 = Saturday
Here, 4 represents Thursday
So, by Zeller s rule 27/06/2019 is on a Thursday.
Question1: By using the above Zeller' s formula, find the day for 15/08/1947.
Question2: By using the above Zeller' s formula, find the day for 26/01/1950.
Answers
15/08/1947 = Friday
26/01/1950 = Thursday
Given : ZEllER’S rule
To Find : Q1: By using the above Zeller' s formula, find the day for 15/08/1947.
Q2: By using the above Zeller' s formula, find the day for 26/01/1950.
Solution:
Question1: 15/08/1947.
F = K + [(13×M – 1)/5] + D + [D/4] + [C/4] -2C
K = 15
M = 6
D = 47
C = 19
F = 15 + [(13×6 – 1)/5] + 47 + [47/4] + [19/4] -2(19)
=> F = 15 + 15 + 47 + 11 + 4 - 38
=> F = 54
54 = 7 x7 + 5
5 = Friday
15/08/1947. FRIDAY
Question2: 26/01/1950.
F = K + [(13×M – 1)/5] + D + [D/4] + [C/4] -2C
K = 26
M = 11
D = 49 ( as Jan & Feb are counted in previous year)
C = 19
F = 26 + [(13×11 – 1)/5] + 49 + [50/4] + [19/4] -2(19)
=> F = 26 + 28 + 49 + 12 + 4 - 38
=> F = 81
81 = 7 x11 + 4
4 = THURSDAY
26/01/1950. THURSDAY
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With this technique named after its founder Zeller, you can solve any ...
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