Question

Gulab jamun contains syrup syrup up to about 30 percentage of its volume find approximately how much would be found in 45 gulab jamun simplex cylinder with hemispherical ends with length 5 cm and diameter 2.8

Answer 1

the length of each gulab jamun =5cm

the diameter of each gulab jamun = 2.8cm

therefore, the radius of each gulab jamun =2.8/2 =1.4cm =radius of the cylinder =radius of the hemisphere

the length of the cylindrical portion =5cm -1.4cm -1.4 cm

=2.2 cm

volume of each gulab jamun =volume of cylinder +volume of 2 hemispheres

=

$\pi {r}^{2} h \\ + 2 \times 2 \div 3\pi {r}^{3}$

$\pi {r}^{2} (h + 4 \div 3r)$

=22/7*14/10*14/10(22/10+4/3+14/10)

=22*28/100(22/10+56/30)

=616/100(66+56/30)

=616/100*122/30 CM cube

therefore, the volume of 45 gulab jamun =616/100*122/30*45

=1127280/1000

=112728/100 CM cube

therefore, the syrup in 45 gulab jamuns =112728/100*30/100 cm cube

=338184/1000 cm cube

=338.184 cm cube

Answer 2

Figure:-

Given:-

• Gulab gulab jamun simplex cylinder with hemispherical ends with length 5 cm and diameter 2.8
• Gulab jamun contains syrup syrup up to about 30 percentage

To find:-

• find approximately how much would be found in 45 gulab jamun..?

Solutions:-

• Radius (r) of cylindrical part = Radius (r) of hemispherical part = 2.8/2 = 1.4 cm.

• Length of each hemispherical part = 5 - 2 × length of hemispherical part.

=> 5 - 2 × 1.4

=> 5 - 2.8

=> 2.2cm

Volume of one gulab jamun = Volume of cylindrical part + 2 × Volume of hemispherical part

=> πr²h + 2 × 2/3πr³ = πr²h + 4/3πr³

=> π × (1.4)² × 2.2 + 4/3 + 4/3π (1.4)³

=> 22/7 × 1.4 × 1.4 × 2.2 + 4/3 × 22/7 × 1.4 × 1.4 × 1.4

=> 22 × 0.2 × 1.4 × 2.2 + 4/3 × 0.2 × 1.4 × 1.4

=> 13.552 + 11.498

=> 25.05cm³

Volume of 45 gulab jamun = 45 × 25.05

=> 1127.25cm³

Volume of sugar syrup = 30%

=> 30/100 × 1127.25

=> 338.17cm³

=> 338cm³

Hence, tne 45 gulab jamun is 338cm³