Math, asked by CarryMinati890, 7 months ago

Gummie 。・:*:・(✿◕3◕)❤

Mr. Jones sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%. On the sale of the pipes, he:

(a) broke even, (b) lost 4 cents, (c) gained 4 cents, (d) lost 10 cents, (e) gained 10 cents​

Answers

Answered by rahulsaab8808
0

Answer:

Lawliet Expert

Let The Cost Price for the first pipe be "x" Dollars

Selling Price = x + 20% of x

1.20 = x + 20x / 100

1.20 = x + x/5

1.20 = (5x + x)/5

1.20 * 5 = 6x

6 = 6x

x = 1 Dollar

So ,

Cost Price of The Pipe in Which Mr. Jones Got Profit of 20% = 1 Dollar

Let The Cost Price Of The Second Pipe be "y" dollar

Selling Price of second Pipe = y - 20% of y

1.20 = y - 20y/100

1.20 = y - y/5

1.20 = (5y - y)/5

1.20 * 5 =4y

6 = 4y

y = 6/4

y = 3/2

y = 1.5 Dollars

Total Cost Price Which Mr Jones Paid = 1 + 1.5

= 2.5 Dollars

Total Selling Price Which Mr Jones Received = 1.2 + 1.2

= 2.4 Dollar

Mr. Jones Lost 10 cents

so,

ANSWER = (d) = lost 10 cents

Hope U Understood

Mark This Brainliest If This Helped You

Thankx

Answered by Anonymous
1

{\huge\bf{\underline{\underline{Solution:-}}}}

\sf{\underline{\purple{Answer-}}}

  • Therefore, Mr. Jones loss 10 cents.

\sf{\underline{\purple{Given-}}}

  • Mr. Jones sold two pipes at $1.20 each. Based on the cost, his profit one was 20% and his loss on the other was 20%.

\sf{\underline{\purple{Explanation-}}}

↦ S.P of the first pipe = $1.20

  • Profit = 20%.

Now, we have to find the C.P of the first pipe.

↦ CP = SP - Profit

↦ CP = 1.20 - 20% of CP

↦ CP = 1.20 - 0.20CP

↦ CP + 0.20CP = 1.20

↦ 1.20CP = 1.20

↦ CP =  \frac{1.20}{1.20}

↦ CP = $ 1

↦ S.P of the Second pipe = $1.20

  • Loss = 20%.

Now, we have to find the C.P of the second pipe.

↦ CP = SP + Loss

↦ CP = 1.20 + 20% of CP

↦ CP = 1.20 + 0.20CP

↦ CP - 0.20CP = 1.20

↦ 0.80CP = 1.20

↦ CP =  \frac{1.20}{0.80}

↦ CP = $1.50

Hence, total CP of the two pipes =$ 1.00 + $1.50 =$ 2.50

And total SP of the two pipes =$1.20 + $1.20 = $2.40

Loss = $ 2.50 - $ 2.40 = $ 0.10

  • Thus, Mr. Jones loss 10 cents.

{\boxed{\sf{C.P=Cost\:Price}}}

{\boxed{\sf{S.P=Selling\:Price}}}

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