gun of mass 2 kg has a bullet of mass 50 gram. if the bullet is fired with a velocity 100ms‐¹, what will be the recoil speed of the gun ?
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Answer:
Is the answer okk?
Explanation:
From the momentum conservation,
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Initially the gun and the bullet was at rest so...
M(0)+m(0)=MV+mv
MV=-mv
Where,M=mass of the gun
V= velocity of the gun
m=mass of the bullet
v= velocity of the bullet
Now..MV=-mv
2000*V=-50*100
V=-5000/2000
V=-2.5m/s
Negative sign indicates that the gun will be recoiled in the opposite direction of the bullet with a recoiled velocity 2.5m/sec
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