gun powder contain 60% nitre, 25% sulphur and rest of it is carbon. find the quantity of nitre and carbon in 48 kg of gun powder.
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Given that gunpowder contains 60% nitre , 25% sulphur and rest is carbon.
So, carbon = 100 - (60+25)
= 100 - 85
= 15%.
Now we need to calculate the amount of nitre and carbon in 48kg of gunpowder.
Let the amount of nitre be x and amount of carbon be y.
Then, 48 × 60/100 = x
24 × 6/5 = x
x = 24 × 1.2
x = 28.8
Now for carbon.
15/100 × 48 = y
3/20 × 48 = y
3/10 × 24 = y
0.3 × 24 = y
y = 7.2
Therefore, in 48kg of gunpowder there is 28.8kg nitre and 7.2kg carbon and 48 - (28.8 + 7.2)
= 48 - 36
= 12kg sulphur.
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So, carbon = 100 - (60+25)
= 100 - 85
= 15%.
Now we need to calculate the amount of nitre and carbon in 48kg of gunpowder.
Let the amount of nitre be x and amount of carbon be y.
Then, 48 × 60/100 = x
24 × 6/5 = x
x = 24 × 1.2
x = 28.8
Now for carbon.
15/100 × 48 = y
3/20 × 48 = y
3/10 × 24 = y
0.3 × 24 = y
y = 7.2
Therefore, in 48kg of gunpowder there is 28.8kg nitre and 7.2kg carbon and 48 - (28.8 + 7.2)
= 48 - 36
= 12kg sulphur.
Please mark as brainliest if it helps you...
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