gun power contains 75% nitre 15% charcoal and the rest sulphur. find the the amount of sulphur in in 9 kilogram of gunpowder.
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Answers
Step-by-step explanation:
The amount of gunpowder =8 kg=8000 g ....[WKT 1 kg=1000 g]
Quantity of nitre in gunpowder =75% of 8000 g
=(75/100)×(8000)
=(75×80)
=6000 g=6 kg
Quantity of sulphur in gunpowder =10% of 8000 g
=(10/100)×8000
=(10×80)
=800 g=0.8 kg
The quantity of charcoal in gunpowder =[8000−(6000+800)]
=[8000−6800]
=1200 g
=1.2 kg
∴ the quantity of charcoal in 8 kg of gunpowder is 1.2 kg
Answer:
The amount of gunpowder =8 kg=8000 g ....[WKT 1 kg=1000 g]
Quantity of nitre in gunpowder =75% of 8000 g
=(75/100)×(8000)
=(75×80)
=6000 g=6 kg
Quantity of sulphur in gunpowder =10% of 8000 g
=(10/100)×8000
=(10×80)
=800 g=0.8 kg
The quantity of charcoal in gunpowder =[8000−(6000+800)]
=[8000−6800]
=1200 g
=1.2 kg
∴ the quantity of charcoal in 8 kg of gunpowder is 1.2 kg
Step-by-step explanation:
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