Math, asked by sudhakar1350, 11 months ago

guna has fixed a single door of 3 feet wide in his home where as Nathan has fixed double door each 1 1/2 feet wide in his room from the closed state if each of the single and double door can open up to 120° whose door requires a minimum area
\pi = 3.14

Answers

Answered by empathictruro
28

Answer:

Guna door require minimum area

Step-by-step explanation:

Area of the sector is given by  (∅÷360)×π×r²

In this case the value of Ф=120

For guna the radius r= 3 feet

For Nathan the radius r = 11÷2 feet

Area covered by guna's door=  3.14×3²÷3

                                                =9.42

Area covered by Nathan's door= 3.14×5.5²÷3

                                                    = 31.66

Answered by tanya507
1

Answer:

Area covered by Nathan's door= 31.66 so Nalthan's door require maximum area.

Step-by-step explanation:

Area of the sector is given by (Ø÷360)×™×r²

In this case the value of 0-120

For guna the radius r= 3 feet

For Nathan the radius r = 11÷2 feet

Area covered by guna's door= 3.14×3²÷3 =9.42

Area covered by Nathan's door= 3.14x5.5²÷3 = 31.66

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