Math, asked by jayaishwariya29, 1 day ago

Guna has fixed a single door of width 42cm in his room where as Nathan has fixed a double door, each of width 21cm in his room. From the closed position, if each of the single and double doors can open up to 120, whose door takes a maximum area.

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Answered by auprocut

Best answer (a) Width of the door that Guna fixed = 3 feet. When the door is open the radius of the sector = 3 feet Angle covered = 120° ∴ Area required to open the door = 120°/360° × πr2 = 120°/360° × π × 3 × 3 = 37π feet2 (b) Width of the double doors that Nathan fixed = 112 feet. Angle described to open = 120° Area required to open = 2 × Area of the sector = 2 × 120°/360° × π × 3/2 × 3/2 feets2 = 3π/2 feet2 = 12 (3π) feet2 ∴ The double door requires the minimum area. Please mark me as brilliant

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Guna has fixed a single door of width 42cm in his room where as Nathan has fixed a double door, each of width 21cm in his room. From the closed position, if each of the single and double doors can open up to 120, whose door takes a maximum area.​

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Guna has fixed a single door of width 42cm in his room where as Nathan has fixed a double door, each of width 21cm in his room. From the closed position, if each of the single and double doors can open up to 120, whose door takes a maximum area.