gunanghand kijiye (4x +3y)2_49z2 answer
Answers
Answered by
0
First, let's break it up into what it looks like:
(4x + 3y) (4x + 3y)
What happens from here is that you multiply the parts in the first parentheses into the second part, so we have:
4x * 4x
4x * 3y
3y * 4x
and 3y * 3y
4 * 4 = 16, x * x = x^2, so 4x * 4x = 16x^2
4 * 3 = 12, x * y = xy, so 4x * 3y = 12xy (and 3y * 4x similarly makes 12xy)
3 * 3 = 9, y * y =y^2, so 3y * 3y = 9y^2
This means our solution so far is:
16x^2 + 12xy + 12xy + 9y^2
Since we have two xy numbers, we can add them together to simplify our final answer to:
16X^2 + 24xy + 9y^2
(4x + 3y) (4x + 3y)
What happens from here is that you multiply the parts in the first parentheses into the second part, so we have:
4x * 4x
4x * 3y
3y * 4x
and 3y * 3y
4 * 4 = 16, x * x = x^2, so 4x * 4x = 16x^2
4 * 3 = 12, x * y = xy, so 4x * 3y = 12xy (and 3y * 4x similarly makes 12xy)
3 * 3 = 9, y * y =y^2, so 3y * 3y = 9y^2
This means our solution so far is:
16x^2 + 12xy + 12xy + 9y^2
Since we have two xy numbers, we can add them together to simplify our final answer to:
16X^2 + 24xy + 9y^2
Similar questions