Math, asked by snigdhasen723, 5 months ago

Guru walks five times around a triangular park of sides 351 m, 146 m

and 543 m while Balu walks 3 times around a square park of side 525 m.

Who walks more and by how much?​

Answers

Answered by yash197911
6

\huge{\tt{\red{answEr:-}}}

Here,

Total distance covered by Guru =5× (Perimeter of triangular park)

\mathcal= 5(351 + 146 + 543) \\  = 5 \times 1040 \\  = 5200 \: m

Total distance covered by Balu = 3×(Perimeter of square park).

 \mathcal  = 3(4 \times 525) \\  = 3 \times 2100 \\  = 6300m

So, we can see that distance covered by Balu is greater than the distance covered by Guru.

Difference between the distances they covered =

 \mathcal(6300 - 5200) m \\  = 1100 \: m

 {\fbox{ \big { \green{So, \: Balu \: covered \: more \: distance \: than \: Guru \: by \: 1100 \: m}}}}

Hope you get helped!!!!

# BeBrainly

\: \: \: \: \: \: \: \:~@yash197911

Answered by Anonymous
8

Answer:

Total distance covered by Guru =5× (Perimeter of triangular park)

\begin{gathered}\mathcal= 5(351 + 146 + 543) \\ = 5 \times 1040 \\ = 5200 \: m\end{gathered}

=5(351+146+543)

=5×1040

=5200m

Total distance covered by Balu = 3×(Perimeter of square park).

\begin{gathered} \mathcal = 3(4 \times 525) \\ = 3 \times 2100 \\ = 6300m\end{gathered}

=3(4×525)

=3×2100

=6300m

So, we can see that distance covered by Balu is greater than the distance covered by Guru.

Difference between the distances they covered =

\begin{gathered} \mathcal(6300 - 5200) m \\ = 1100 \: m\end{gathered}

(6300−5200)m

=1100m

{\fbox{ { \green{So, \: Balu \: covered \: more \: distance \: than \: Guru \: by \: 1100 \: m}}}}

So, Balu covered more distance than Guru by 1100 m

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