Gus please help me with this triangles question
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OmShinde76:
Arre baba
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Proof:
In right triangles AEB and AEC, using Pythagoras theorem
AB2 + AC2 = BE2 + AE2 + EC2 + AE2 = 2AE2 + (BD - ED)2 + (ED + DC)2
= 2AE2 + 2ED2 + BD2 + DC2
so that BD=DC
AB2 + AC2 = 2AE2 + 2ED2 + 2BD2 [since BD = DC]
= 2 (AE2 + ED2 + BD2)
= 2 (AD2 + BD2)
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