Question

Guys 15 th answer please fast as u can

Answer 1

A.P = 5, 15, 25,........

d = 15-5

   = 10

31st term = a+30d

               = 5+30 X 10

               = 5+300

               = 305

305+130 = 435

let an = 435

a+(n - 1)d = 435

5+ (n - 1)10 = 435

5+10n - 10 = 435

10n - 5 = 435

10n = 435+5

10n = 440

n = 44

Therefore, the 44th term of A.P is 130 more than its 31st term

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Answer 2

a = 5

d = 10

a31 = a + 30d

a31 = 5 + 30 × 10

a31 = 5 + 300

a31 = 305

A.T.Q.

The term which is 130 more than its 31st term is

= a31 + 130

= 305 + 130

= 435

l = a + ( n - 1 )d

435 = 5 + ( n - 1 ) × 10

435 - 5 = 10n - 10

430 + 10 = 10n

440 = 10n

n = 440/10

n = 44

Hence,

The 44th term is 130 more than its 31st term.

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