Computer Science, asked by dibyendu16, 8 months ago

GUYS 50 POINTS ENJOY BUT PLZ GIVE THE CURRECT ANSWER . A school conducts three exams namely term1, term 2 and final-term exams. Final marks scored (weighed marks) are computed as 30% of term1 + 30% of term 2 + 40% of the final-term marks. Write a program to compute the weighted marks for a student who scored 412 in first term, 423 in second term and 430 in third (final) term. Then compute the weighted percentage out of 500 marks.

Answers

Answered by naghmashahid03
0

Marks got in 1st,2nd and 3rd term : 412,423 and 430 out of 500.

Weightage of 1st,2nd and 3rd term : 30%,30% and 40%

To find :

Weightage percentage.

Solution :

In first term number got : 412 out of 500.

So, % number in first term :

\frac{412 \times 100}{500} = 82.4\%500412×100=82.4%

In second term number got : 423 out of 500.

So, % number in second term :

\frac{423\times 100}{500} = 84.6\%500423×100=84.6%

In third term number got : 430 out of 500.

So,% number in third term :

\frac{430 \times 100}{500} = 86\%500430×100=86%

Weightage of first term = 30 %

So, % weightage got in first term :

\frac{82.4 \times 30}{100} = 24.72\%10082.4×30=24.72%

Weightage of second term = 30 %

So, % weightage got in second term :

\frac{84.6\times 30}{100} =25.38\%10084.6×30=25.38%

Weightage of third term = 40 %

So, % weightage got in third term :

\frac{86 \times 40}{100} = 34.4\%10086×40=34.4%

Total weightage percentage of three exams :

(24.72 + 25.38 + 34.4 )% = 84.50 %

Answered by pAvIKTm46
0

Answer:

Marks got in 1st,2nd and 3rd term : 412,423 and 430 out of 500.

Weightage of 1st,2nd and 3rd term : 30%,30% and 40%

To find :

Weightage percentage.

Solution :

In first term number got : 412 out of 500.

So, % number in first term :

\frac{412 \times 100}{500} = 82.4\%

500

412×100

=82.4%

In second term number got : 423 out of 500.

So, % number in second term :

\frac{423\times 100}{500} = 84.6\%

500

423×100

=84.6%

In third term number got : 430 out of 500.

So,% number in third term :

\frac{430 \times 100}{500} = 86\%

500

430×100

=86%

Weightage of first term = 30 %

So, % weightage got in first term :

\frac{82.4 \times 30}{100} = 24.72\%

100

82.4×30

=24.72%

Weightage of second term = 30 %

So, % weightage got in second term :

\frac{84.6\times 30}{100} =25.38\%

100

84.6×30

=25.38%

Weightage of third term = 40 %

So, % weightage got in third term :

\frac{86 \times 40}{100} = 34.4\%

100

86×40

=34.4%

Total weightage percentage of three exams :

(24.72 + 25.38 + 34.4 )% = 84.50 %

Explanation:

Hopes it help❤️

Similar questions