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Hey mate here is your answer
Answer:
In △AEC AND △ADB
∠A = ∠A (Common)
∠AEC = ∠ADB (90* Each)
--△AEC ~ △ADB (AA)
=AE/AD = AC/AB = EC/DB (Corresponding sides of similar △'s are proportional)
=AE/AD = AC/AB
Therefore, AE x AB = AC x AD
Hope it helped you :)
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