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8) Given that,
SinA+Sin²A=1
SinA=1-sin²A
Now,
Cos²A+cos⁴A=cos²A(1+Cos²A)
=1-sin²A(1+1-sin²A)
=sinA(1+SinA)
=SinA+Sin²A=1
9) Given,
5tan²A-5sec²A+1
=-5(Sec²A-tan²A)+1
=-5(1)+1
=-5+1=-4
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