Question

guys answer this question plz

Answer 1

Answer:

$\dfrac{3^2 \times 7^8 \times 13^6}{21^2 \times 91^3}$

$\implies \dfrac{3^2 \times 7^8 \times 13^6}{(3\times 7)^2 \times (13 \times 7)^3}$

$\implies \dfrac{3^2 \times 7^8 \times 13^6}{3^2 \times 7^2 \times 13^3 \times 7^3}$

$\implies \dfrac{3^2 \times 7^8 \times 13^6}{3^2 \times 7^5 \times 13^3}$

$\implies 3^{2-2} \times 7^{8-5} \times 13^{6 - 3}$

$\implies 3^0 \times 7^3 \times 13^3$

$\implies 1 \times 343 \times 2197$

$\boxed{\implies{\boxed{753571}}}$

Additional information:

• $a^m \times a^n = a^{m+n}$

• $\dfrac{a^m}{a^n} = a^{m-n}$

• $a^m \times b^m = (ab)^m$

• $a^m = b^m \implies a = b$

• $a^m = a^n \implies m = n$

Answer 2

753571 is your answer for the question