Question

guys answer to this plz​

Answer 1

Given -

• $\displaystyle{\sf{2^{\frac{2}{3}} . 2^{\frac{1}{3}}}}$

⠀

Solution -

We can solve this exponential problem by using the given identity

• $\bf{\red{a^x . a^y = a^{x + y}}}$

⠀

$\tt{\longrightarrow{2^{\frac{2}{3}} . 2^{\frac{1}{3}}}}$

⠀

$\tt{\longrightarrow{2^{\frac{2}{3} + \frac{1}{3}}}}$

⠀

$\tt{\longrightarrow{2^{\frac{2 + 1}{3}}}}$

⠀

$\tt{\longrightarrow{2^{\frac{3}{3}}}}$

⠀

$\tt{\longrightarrow{2^1}}$

⠀

$\bf{\longrightarrow{\purple{2}}}$

⠀

Hence,

• The required value is 2.

━━━━━━━━━━━━━━━━━━━━━━

Answer 2

Answer:

Given -

\displaystyle{\sf{2^{\frac{2}{3}} . 2^{\frac{1}{3}}}}2

3

2

.2

3

1

⠀

Solution -

We can solve this exponential problem by using the given identity

\bf{\red{a^x . a^y = a^{x + y}}}a

x

.a

y

=a

x+y

⠀

\tt{\longrightarrow{2^{\frac{2}{3}} . 2^{\frac{1}{3}}}}⟶2

3

2

.2

3

1

⠀

\tt{\longrightarrow{2^{\frac{2}{3} + \frac{1}{3}}}}⟶2

3

2

+

3

1

⠀

\tt{\longrightarrow{2^{\frac{2 + 1}{3}}}}⟶2

3

2+1

⠀

\tt{\longrightarrow{2^{\frac{3}{3}}}}⟶2

3

3

⠀

\tt{\longrightarrow{2^1}}⟶2

1

⠀

\bf{\longrightarrow{\purple{2}}}⟶2

⠀

Hence,

The required value is 2.

━━━━━━━━━━━━━━━━━━━━━━

Step-by-step explanation:

thanks Venomnobita