Math, asked by kashmachannel266, 6 hours ago

GUYS CAN ANYONE ANSWER IT IMMEDIATELY PLEASE
I WILL MARK THE CORRECT
AS THE BRAINLIEST PLEASEEEEE
JUST SOLVE FOR X PLEASEEEEE​

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Answers

Answered by aniketrupa2011
0

Combine multiplied terms into a single fraction

2

Distribute

3

(

5

)

8

=

9

2

\frac{{\color{#c92786}{3(x-5)}}}{8}=9-2x

83(x−5)=9−2x

3

1

5

8

=

9

2

\frac{{\color{#c92786}{3x-15}}}{8}=9-2x

83x−15=9−2x

3

Rearrange terms

3

1

5

8

=

9

2

\frac{3x-15}{8}={\color{#c92786}{9-2x}}

83x−15=9−2x

3

1

5

8

=

2

+

9

\frac{3x-15}{8}={\color{#c92786}{-2x+9}}

83x−15=−2x+9

4

Add

2

2x

2x

to both sides of the equation

3

1

5

8

=

2

+

9

\frac{3x-15}{8}=-2x+9

83x−15=−2x+9

3

1

5

8

+

2

=

2

+

9

+

2

\frac{3x-15}{8}+{\color{#c92786}{2x}}=-2x+9+{\color{#c92786}{2x}}

83x−15+2x=−2x+9+2x

5

Simplify

Find common denominator

Combine fractions with common denominator

Multiply the numbers

Combine like terms

Combine like terms

1

9

1

5

8

=

9

\frac{19x-15}{8}=9

819x−15=9

6

Multiply all terms by the same value to eliminate fraction denominators

1

9

1

5

8

=

9

\frac{19x-15}{8}=9

819x−15=9

8

1

9

1

5

8

=

8

9

8 \cdot \frac{19x-15}{8}=8 \cdot 9

8⋅819x−15=8⋅9

7

Cancel multiplied terms that are in the denominator

8

1

9

1

5

8

=

8

9

8 \cdot \frac{19x-15}{8}=8 \cdot 9

8⋅819x−15=8⋅9

1

9

1

5

=

8

9

19x-15=8 \cdot 9

19x−15=8⋅9

8

Multiply the numbers

1

9

1

5

=

8

9

19x-15={\color{#c92786}{8}} \cdot {\color{#c92786}{9}}

19x−15=8⋅9

1

9

1

5

=

7

2

19x-15={\color{#c92786}{72}}

19x−15=72

9

Add

1

5

15

15

to both sides of the equation

1

9

1

5

=

7

2

19x-15=72

19x−15=72

1

9

1

5

+

1

5

=

7

2

+

1

5

19x-15+{\color{#c92786}{15}}=72+{\color{#c92786}{15}}

19x−15+15=72+15

10

Simplify

11

Divide both sides of the equation by the same term

1

9

=

8

7

19x=87

19x=87

1

9

1

9

=

8

7

1

9

\frac{19x}{{\color{#c92786}{19}}}=\frac{87}{{\color{#c92786}{19}}}

1919x=1987

12

Simplify

Cancel terms that are in both the numerator and denominator

1

9

1

9

=

8

7

1

9

{\color{#c92786}{\frac{19x}{19}}}=\frac{87}{19}

1919x=1987

=

8

7

1

9

{\color{#c92786}{x}}=\frac{87}{19}

x=1987

=

8

7

1

9

Answered by pushpanjalisingh1978
0

Answer:

x = 87/19

Step-by-step explanation:

3/8(x-5) is same as 3(x-5)/8

so, now solving it we will get 3x-15/8

Now, 3x-15/8 = 9-2x

Now, multiply 8 on both sides

so, it will be 3x-15=(9-2x) * 8

Now, 3x-15=72-16x

so, 19x=72+15

so, 19x=87

Now, transpose 19 to RHS of equation

so, the answer will be x=87/19

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IF YOU GET HE ANSWER RIGHT

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