Question

Guys, can anyone proof

${v}^{2} = {u}^{2} + 2as$
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Answer 1

Answer:

s = ut + 1/2 at sq. becomes

s = u [ v- u /a] + 1/2 a [ v- u /a ] sq.

2as = 2v (v-u) + (v-u) sq.

2as= 2uv-2usq. -vsq. - 2uv - usq.

2as= vsq. - usq.

vsq. = usq. + 2as

I hope it help you......

Answer 2

this photo is your answer