guys can anyone solve all the level one please
only 2 question
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Answer:
k = 7
Step-by-step explanation:
GIVEN :
x² - ( k + 6 ) x + 2 ( 2k - 1 ) has roots as α and β
Also, ( α + β ) = 1/2 αβ
TO FIND : Value of k.
SOLUTION :
x² - ( k + 6 ) x + 2 ( 2k - 1 ) as ax² + bx + c =0
Gives, a = 1 , b = - ( k + 6 ) & c = 2 ( 2k - 1 )
As we know that
sum of zeros of a quadratic equation,
( α + β ) = - b/a
so, ( α + β ) = ( k + 6 )
Product of zeros ,
αβ = c/a = 2 ( 2k - 1 )
But As ( α + β ) = 1/2 αβ
so, ( k + 6 ) = 1/2 x 2 ( 2k - 1 )
or , ( k + 6 ) = ( 2k - 1 )
or, k = 7
So, the value of comes to be 7 according to the condition.
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tune kisko stupiiid kaha woh toh tu hi hai
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