Question

GUYS CAN ANYONE SOLVE THIS QUESTION??​

Answer 1

Answer:

${a}^{3} + {b}^{3} = (a + b)( {a}^{2} + {b}^{2} - ab) \\ \\ \\ \frac{0.75 \times 0.75 \times 0.75 + 0.25 \times 025 \times 0.25}{0.75 \times 0.75 - 0.75 \times 0.25 + 0.25 \times 0.25} = 1 \\ \frac{ ({0.75})^{3} + {(0.25)}^{3} }{ ({0.75)}^{2} - 0.75 \times 0.25 + ({0.25})^{2} } \\ \\ \\ using \: formula \\ \frac{(0.75 + 0.25)( {0.75}^{2} + {0.25}^{2} - 0.75 \times 0.25) }{(0.75) {}^{2} + (0.25) {}^{2} - 0.75 \times 0.25 } \\ \\ (0.75 + 0.25 \\ = 1 \\ hence \: proved \: \\ lhs = rhs$

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