Math, asked by royals2, 3 months ago

Guys, do solve this question.​

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Answered by priyasha366
1

Step-by-step explanation:

tanA- cotA / sincosA (sinA - cosA)

sin/cos - cos/sin / sincosA (sinA - cos A)

sin² - cos²/ sincos / sincos (sin -cos)

sin² - cos² / sin²cos² (sin - cos)

(sin +cos)(sin - cos)/ (sin- cos) sin²cos²

sin + cos / sin² cos² = L.H.S

1/cos * 1/sin (1/cos + 1/sin)

1/cos * 1/sin * sin + cos / sincos

sin + cos / sin² cos²  = R.H.S

L.H.S = R.H.S

hence proved


royals2: I just solved it and checked whether someone answered or not and your answer popped in notifications. Great. Thanks a lot.
priyasha366: you're welcome
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