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Claculate the molarity of the following solution:
1.0 moles of HCL in 750cm3 of solution :
a.) 0.1 M
b.) 0.5 M
c.) 2 M
d.) 0.025 M
[No problems if you dont write the whole method. I only need answer].
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Answer:
Approx. 1.3 mol⋅L−1 with respect to KCl .
Explanation:
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