guys give me the answer.........#brainliest
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Explanation:
TOTAL INDIVIDUALS = 6000
INDIVIDUALS WITH RECESSIVE DISEASE = 60
FREQUENCY OF RECESSIVE GENES aa = a² = 60/6000
aa=1/100
a²=(1/10)², A= 1/10
WE KNOW ,ACCORDING TO HARDY WEINBERG EQUILIBRIUM
A+a = 1
A+1/10= 1
A = 1-1/10
A = 9/10
A= 0.9
FREQUENCY OF A²=(0.9)²=0.81.
HOPE THIS HELPS.
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