Question

guys give me the answer.........#brainliest ​

Answer 1

Answer:

Explanation:

TOTAL INDIVIDUALS = 6000

INDIVIDUALS WITH RECESSIVE DISEASE = 60

FREQUENCY OF RECESSIVE GENES aa = a² = 60/6000

aa=1/100

a²=(1/10)², A= 1/10

WE KNOW ,ACCORDING TO HARDY WEINBERG EQUILIBRIUM

A+a = 1

A+1/10= 1

A = 1-1/10

A = 9/10

A= 0.9

FREQUENCY OF A²=(0.9)²=0.81.

HOPE THIS HELPS.