Question

Guys give reason for the answer

Answer 1

Let the Volume of Oil that Tin can hold be : T

$\mathsf{Given : The \ Tin \ of \ Oil \ was \ \dfrac{4}{5} \ full}$

$\implies \mathsf{Volume \ of \ Oil \ in \ the \ Tin \ was : \bigg(\dfrac{4}{5} \times T\bigg)}$

$\textsf{Given : 6 bottles of oil were taken out and 4 bottles of oil were poured into}\\ \textsf{it, then the Volume of Oil in the Tin was \mathsf{\bigg(\dfrac{3}{4} \times T\bigg)} }$

Let the Volume of Oil a bottle can hold be : B

$\implies \mathsf{\dfrac{4T}{5} - 6B + 4B = \dfrac{3T}{4}}$

$\implies \mathsf{\dfrac{4T}{5} - 2B = \dfrac{3T}{4}}$

$\implies \mathsf{2B = \dfrac{4T}{5} - \dfrac{3T}{4}}$

$\implies \mathsf{2B = \dfrac{16T - 15T}{20}}$

$\implies \mathsf{2B = \dfrac{T}{20}}$

$\implies \mathsf{B = \dfrac{T}{40}}$

$\textsf{It means each Bottle holds \mathsf{\bigg(\dfrac{1}{40}\bigg)^{th}} Volume of Oil of the Tin}$

$\implies \textsf{Tin can contain 40 bottles of oil}$

Answer : Option [c]