Math, asked by Raiden123, 1 year ago

guys help... it's for exam..plz help

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Answered by Naina549
0
log xy^3=m
log x+log y^3 =m
log x+3log y =m-------------(1)
log x^3y^2=p
log x^3+log y^3=p
3log x +2log y=m-------------(2)
after solving simultaneous you will get the values of log x and log y
log(x^2/y)= log x^2 - log y
=2log x -log y
put it in the above equation
Answered by PravinRatta
0

Answer:

Step-by-step explanation:

Given that

log xy^3= m

This can be written as by applying log rules

log x+log y^3 = m

log x+3 log y = m------(i)

log x^3y^2=p

Apply log rules,

log x^3+log y^3=p

3 log x +2 log y = m -------(ii)

After solving simultaneous you will get the values of log x and log y

log(x^2/y)= log x^2 - log y

=2 log x - log y

on putting the value from above equation you can find out the answer in term of m and p.

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