guys help... it's for exam..plz help
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log xy^3=m
log x+log y^3 =m
log x+3log y =m-------------(1)
log x^3y^2=p
log x^3+log y^3=p
3log x +2log y=m-------------(2)
after solving simultaneous you will get the values of log x and log y
log(x^2/y)= log x^2 - log y
=2log x -log y
put it in the above equation
log x+log y^3 =m
log x+3log y =m-------------(1)
log x^3y^2=p
log x^3+log y^3=p
3log x +2log y=m-------------(2)
after solving simultaneous you will get the values of log x and log y
log(x^2/y)= log x^2 - log y
=2log x -log y
put it in the above equation
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Answer:
Step-by-step explanation:
Given that
log xy^3= m
This can be written as by applying log rules
log x+log y^3 = m
log x+3 log y = m------(i)
log x^3y^2=p
Apply log rules,
log x^3+log y^3=p
3 log x +2 log y = m -------(ii)
After solving simultaneous you will get the values of log x and log y
log(x^2/y)= log x^2 - log y
=2 log x - log y
on putting the value from above equation you can find out the answer in term of m and p.
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